The factoring method cannot be used on quadratic equations that are not factorable. Does this mean that they cannot be solved in the set of real numbers? For some quadratic equations, the answer is yes, but many can be solved by different methods. Mathematics generally allows for more than one way to solve a problem, and there are several methods for solving quadratic equations. Match the square root with its perfect square:

1. 1
√144
2. 6
√100
3. 12
√49
4. 10
√16
5. 3
√25
6. 13
√36
7. 11
√4
8. 4
√64
9. 8
√169
10. 5
√9
11. 9
√1
12. 7
√81
13. 2
√121

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

welcome!

3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.

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