Given the vector u with magnitude 8 and direction 150° and the vector v with magnitude 3 and direction 115º, find the components of the vector u + v. Round to four decimal places

Explanation:

Vector u has magnitude 8 and direction 150 degrees.

So r = 8 and theta = 150

The polar form

r*(cos(theta)+i*sin(theta))

updates to

8*(cos(150)+i*sin(150))

Use your calculator to evaluate that last expression to get it into a+bi form

8*(cos(150)+i*sin(150))

8*(-0.866025 + i*0.5)

-6.9282 + 4i

So this is the a+bi form of vector u. It's a rough approximation of it.

Repeat those steps for vector v

v = r*(cos(theta)+i*sin(theta))

v = 3*(cos(115)+i*sin(115))

v = 3*(-0.422618 + i*0.906308)

v = -1.267854 + 2.718924i

We're converting each vector to a+bi form so that we can add the vectors.

The general idea is that if you want to add v = a+bi and w = c+di, then

v+w = (a+c)+(b+d)i

we simply add the corresponding real components together, and the imaginary components are added together as well.

Add up u and v

u+v = (-6.9282 + 4i) + (-1.267854 + 2.718924i)

u+v = (-6.9282 + -1.267854) + (4i + 2.718924i)

u+v = -8.196054 + 6.718924i

When rounding to four decimal places, the real and imaginary components are -8.1961 and 6.7189 respectively. These represent the x and y components of the vector.

So we can say vector u+v is approximately < -8.1961, 6.7189 >

ik how do do this just give me a few minutes and i will give it to

idk what the heck he answer is, i’m just putting this here so i finish my account