PLSS HELP!! DUE TODAY The sum of 4 consecutive integers is 82. Write and solve an equation to determine what the first number is. Then, find the other numbers.

Select the equation that goes with the word problem.
A: 0+x+(x+1)+(x+2)
B : x+(x+1)+(x+2)+(x+3)
C : (x+1)+(x+2)+(x+3)+(x+4)
D : (x+2)+(x+3)+(x+4)+(x+5)

What is the first number?
___

What are the next three numbers?
• 17,18,19
• 18,19,20
• 19,20,21
• 20,21,22

Equation: x + (x + 1) + (x + 2) + (x + 3)

First number: 19

Next three numbers: 20, 21, 22

Step-by-step explanation:

Consecutive numbers are numbers that are are next to each other. In this case, the problem is referring to integers that are in ascending order. In essence, each number in this pattern will be one greater than the last. If one calls the first number (x), then one can represent the sum of the four consecutive numbers with the following:

x + (x + 1) + (x + 2) + (x + 3)

It is given that the sum of these number is (82), therefore one can form an equation and solve:

x + (x + 1) + (x + 2) + (x + 3) = 82

Simplify,

x + x + 1 + x + 2 + x + 3 = 82

4x + 6 = 82

Inverse operations:

4x + 6 = 82

4x = 76

x = 19

Succeding numbers in this pattern:

20, 21, 22

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5

can you post the graph?