Two runners are participating on a 720-metre circular track. They run in opposite directions, each at a constant speed. The first runner needs four minutes to complete the full loop and the second runner needs five minutes. How many metres does the second runner travel between two consecutive meetings of the two runners?

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320m

Step-by-step explanation:

let the two runners be A and B

with Va and Vb as their velocities

velocity=distance/time

Va=720/4*60

=3m/s

Vb=720/5*60

=2.4m/s

Let the 2 runners start from a common position X and meet at Y

so the 2 consecutive meetings happen at X and Y

so we have to find time of meeting at Y as we know that of X (which is t=0)

720=Va*t+Vb*t

t(5.4)=720

t=133.33 or t=720/5.4

therefore distance travelled by B =Vb*t

=2.4*720/5.4

=319.99m

=320m

if x decreases by 4 then y increases by 10

step-by-step explanation:

step-by-step explanation: