Nicky wants to surround a 25 in. by 16 in. painting with a frame that is w inches wide. Which quadratic function represents the combined area A of the picture and the frame? A. A(w) = 4w2 + 32w + 400
B. A(w) = 4w2 + 42w + 400
C. A(w) = 4w2 + 64w + 400
D. A(w) = 4w2 + 82w + 400

Option "D" is the correct answer to the following question.

Step-by-step explanation:

Given:

Length of painting = 25 inch

Height of painting = 16 inch

Width of frame = w inch

Find:

Area of Picture with frame

Computation:

New length of painting = 25 + w + w

New length of painting = 25 + 2w inch

New height of painting = 16 + w + w

New height of painting = 16 + 2w

Area = l x b

So,

Area of Picture with frame = [25 + 2w][16 + 2w]

Area of Picture with frame = 400 + 50w + 32w + 4w²

Area of Picture with frame = 4w² + 82w + 400

something that characterises a right triangle is the fact that we may use pythagoras' theorem to find any one of its sides given that we have the length of the other two sides. here, we have the length of the hypotenuse, √(87) yd, and one other side, √(23) yd, thus we can easily find the length of the remaining side using pythagoras' theorem as defined below:

c^2 = a^2 + b^2, where c is the length of the hypotenuse, and a and b are the lengths of the other two sides.

thus, given that c = √(87) and a = √(23), we may substitute these into the formula we defined above to get:

c^2 = a^2 + b^2

(√87)^2 = (√23)^2 + b^2 (substitute c = √87 and a = √23 into the equation)

87 = 23 + b^2 (evaluate (√87)^2 = 87 and (√23)^2 = 23 - remember that the square root of a number, squared will equal that very same number)

64 = b^2 (subtract 23 from both sides)

√64 = b (take the square root of both sides)

8 = b (evaluate √64 = 8)

therefor, the length of the unknown leg in the right triangle is 8 yd (first answer).

d

step-by-step explanation: