PLS HELP LIKE I NEED SLEEP SO BAD BUT MATH HW the price of Stock A at 9 A. M. was ​$13.63. Since​ then, the price has been increasing at the rate of ​$0.13 each hour. At noon the price of Stock B was ​$14.38. It begins to decrease at the rate of ​$0.15 each hour. If the two rates​ continue, in how many hours will the prices of the two stocks be the​ same?

x = 4.29 hours

Step-by-step explanation:

Let

x = number of hours

Stock A at 9.00 AM

13.63 + 0.13x

Stock B at 12.00 pm

14.38 - 0.15(x - 3)

in how many hours will the prices of the two stocks be the​ same?

Equate the change in prices of both stock

13.63 + 0.13x = 14.38 - 0.15(x - 3)

13.63 + 0.13x = 14.38 - 0.15x + 0.45

13.63 + 0.13x = 14.83 - 0.15x

13.63 - 14.83 = -0.15x - 0.13x

-1.2 = -0.28x

x = -1.2/-0.28

x = 4.2857142857142

Approximately,

x = 4.29 hours

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

1 1/5

step-by-step explanation: