Find the center and radius of the circle whose equation is x 2 + y 2 - 6x - 2y + 4 = 0 (3,1), r = /6
(-3,-1), r = /6
(3,1) r = 6
(9,1), r = 36

Solution given:

the equation of a circle is:

x²+y²-6x-2y+4=0

x²-2*x*3+3²+y²-2y+1²-1²+4=0

(x-3)²+(y-1)²=9+1-4

(x-3)²+(y-1)²=6

comparing above equation with

(a-h)²+(y-k)²=r²

we get

centre (h,k)=(3,1)

radius=√6

option first

(3,1), r = √6 is a required answer.

(3,1), r = √6 is a required answer.

Step-by-step explanation: