Which of the following shows that the sum of two irrational numbers can be irrational? A. (5+π)+(3-π)
B. √3+√5
C. (3+√5)+(3-√5)
D. (π/3)+(-π/3)

Given:

The sum of irrational number in the options.

To find:

The option that shows the sum of two irrational numbers can be irrational.

Solution:

In option A,

We know that 8 is a rational number. So, option A is incorrect.

In option B,

Here both numbers are irrational and it cannot be simplified further.

So, is an irrational number and option B is correct.

In option C,

We know that 6 is a rational number. So, option C is incorrect.

In option D,

We know that 0 is a rational number. So, option D is incorrect.

Therefore, the correct option is B.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3