Please show your work. I want to actually understand this. thank you kindly :) 6 problems

Solve with substitution

1)
y = 8x - 6
y = 3x - 1

2)
y = 4x + 18
5x - 6y = -13

3)
y = -3x + 6
-9x - 3y = 7

4)
2x - y = -10
y = 2x + 10

5)
y = -7x - 10
-x - 5y = -18

6)
y = x - 1
-x - y = -19

x= -3 and

step-by-step explanation:

to find the roots of a cubic, use division or factoring to find the factors then set equal to 0. as this is a difference of cubes, it factors into

where a is the cube root of .

here   this is 27 and the cube root of 27 is 3. so we write using the form:

.

set each factor to 0 and solve for x.

x-3=0

x=3

the quadratic expression does not factor and must be solved using the quadratic formula.

where a = 1, b=3, and c=9

this cubic has two complex roots.

good luck on ur quiz test or homework. have a good day : )