A manufacturer has determined that for every 1000 units it produces, 3 will be faulty. What is the probability that an order of 50 units will have one or more faulty units

0.1393 = 13.93% probability that an order of 50 units will have one or more faulty units.

Step-by-step explanation:

Mean for a number of units, which means that the Poisson distribution is used to solve this question.

Poisson Distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which

x is the number of sucesses

e = 2.71828 is the Euler number

is the mean in the given interval.

Mean:

3 defective for 1000, how many for 50?

3 - 1000

- 50

Applying cross multiplication:

What is the probability that an order of 50 units will have one or more faulty units?

This is:

In which

0.1393 = 13.93% probability that an order of 50 units will have one or more faulty units.

. + λrh() e 1 1 2 4 4 4 4 4 3 4 4 4 4 4 + th−1(− s(x)2 dx ω + λrh−1() e 2 1 2 4 4

step-by-step explanation:

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation: