To spherical balls of wax are tightly fitted into a cylinder you know that the wax balls have a radius of 3 cm as does the cylinderYou need to figure out how Highup in the cylinder the wax will rise when the balls are melted show your work and clearly indicate your final answer for h. What is the total volume of both balls express your answers in terms of possible.

Assume there is no change in volume of wax after it has melted after melting what shape of the wax

What is the height of the wax inside the cylinder after it completely melts

1.true 2.false? ? i think. .

step-by-step explanation:

step-by-step explanation:

answer: 180 degrees clockwise

step-by-step explanation:

part a: triangles gcb and epb

part b. sides cg and rp are parallel by definition of parallelogram.

angles cgb and e are congruent by being alternate interior angles of parallel lines cut by a transversal. angles gbc and ebp are congruent because they are vertical angles. by aa similarity, the triangles are similar.

part c. since the triangles are similar, the ratios of the lengths of corresponding sides are equal.

calculation of be:

gb/be = cb/bp

(400 ft)/be = 300/200

(400 ft)/be = 3/2

3be = 2 * 400 ft

3be = 800 ft

be = 800/3 ft

calculation of pe:

gc/pe = cb/bp

(350 ft)/pe = 300/200

(350 ft)/pe = 3/2

3pe = 2 * 350 ft

3pe = 700 ft

pe = 700/3 ft