Playing with toy alphabet blocks, Suzie mixes three of the ABCDE blocks into some combination (doesn't care about the order.) Then she takes the XYZ blocks and carefully puts these into a specific order. How many different outcomes are possible for this arrangement of six blocks?

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

eww xbox also eww dayz

step-by-step explanation:

just for that im not answering