Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 6.8 parts/million (ppm). A researcher believes that the current ozone level is at an insufficient level. The mean of 10 samples is 6.4 ppm with a standard deviation of 1.1. Does the data support the claim at the 0.05 level

The test statistics fall in the critical region and hence null hypothesis is to be rejected.

Step-by-step explanation:

The null hypothesis : H0 : Mean = 6.80  

Alternative hypothesis: Ha: Mean is not equal to 6.80

As per the z statistics  

z = (x’-mean)/(sigma/sqrt n)

Substituting the given values, we get –  

z = 6.4-6.8/(1.1/sqrt 10)

z = -1.149

z test statistics is -1.149

Critical value for two tailed test at 98% confidence is .10749

The test statistics fall in the critical region and hence null hypothesis is to be rejected.

i really dont know

step-by-step explanation:

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !