Suppose that a large mixing tank initially holds 1200 L of water in which 25 kg of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 10 L/min, and when the solution is well stirred, it is then pumped out at a slower rate of 7.5 L/min. If the concentration of the solution entering is 0.25 kg/L, determine a differential equation for the amount of salt A(t) in the tank at time t > 0. (Use A for A(t).)

step-by-step explanation:

the given growth  function for the length of the fish (cm) is

f(m) = 5(1.07)m = 5.35m

where 

m = months

at the end of the study, the length is 9.19 cm. the  time for conducting the study is determined as

5.35m = 9.19

m = 1.7178 months

part a.

the study was performed over a time period  of about 1.72 months. therefore  the domain for  plotting the function is 0 < = m < = 1.72.

note:

if growth  continues at this rate for up to m months, then the domain would be 0< =m< =m.

part b.

the growth function is a linear function.

when m=0, f=0.

therefore the initial growth is zero, which represents the y-intercept.

part c.

assume that the growth function is valid for 0< =m< =9.

the average rate of change of the function is the slope of the linear function, which is 5.35 cm/month.