A ball is kicked from a height of 3 feet above ground the height of the ball is h(t) is given by h(t) = 5t raised to the 2 power +14t+3 where t is the time in seconds after the ball is kicked. How long will it take the ball to hit the ground after kicked?

t = -2.566s and -1.169s

Step-by-step explanation:

Given the height of the ball expressed at

h(t) = 5t²+14t+3

The ball will hit the ground at h(t) = 0

Substitute and get t

0 = 5t²+14t+3

Use general formula

t = -14+/- √14²-4(5)(3)/2(5)

t = -14+/- √196-60)/10

t = -14+/- √136/10

t =-14+/- 11.66/10

t = -25.66/10 and -2.338/2

t = -2.566s and -1.169s

Hence the ball will hit the ground at these times

5

step-by-step explanation: