As an avid golfer, you want to estimate your average score for 18 holes of golf. Suppose you know that the standard deviation of your score is 16.425 strokes and you want to find a sample mean that is within 5.947 strokes of your true average for all rounds of golf with 90% confidence. How many rounds would you need to play to determine this

21

Step-by-step explanation:

Given that

The holes of golf is 18

The standard deviation of the score is 16.425 strokes

The sample mean is 5.947

And, there is 90% confidence

We need to find out the number of rounds

So,

At 90% confidence interval, the critical value is +/- 1.645

Margin of error = 5.947

Z_0.05 × SD/sqrt (n) = 5.947

1.645 × 16.425/sqrt (n) = 5.947

sqrt(n) = 1.645 × 16.425 ÷ 5.947

sqrt(n) = 4.54

= 21

d: (13,-1)

step-by-step explanation:

we know the starting point is (1,5)

the ending point is (x,y)   (cristians house)

the total distance is 6 units (5: 1)  

the fast food restaurant is at (11,0) and is 5/6ths of the way from the starting point to the ending point

ending minus starting point * 5/6   is how far they went

(x-1) *5/6, (y-5) * 5/6

we then need to add the starting point to determine the location

5/6(x-1) + 1, (y-5) * 5/6 + 5

this equals the fast food location of 11,0

setting the x locations equal

5/6 (x-1) +1 =11

subtracting 1 from each side

5/6 (x-1) +1-1 =11-1

5/6(x-1) =10

multiplying by 6/5 on each side

6/5*5/6(x-1) = 10*6/5

x-1 =12

add 1 to each side

x-1+1 =12+1

x=13

do the same for the y coordinate

(y-5) * 5/6 + 5 =0

subtract 5 from each side

(y-5) * 5/6 + 5-5 =0-5

5/6 (y-5) = -5

multiplying by 6/5 on each side

6/5*5/6 (y-5) = -5 *6/5

y-5 = -6

add 5 to each side

y-5+5 = -6+5

y=-1

the ending point , or the coordinates of cristians house is

(13,-1)