If h(x) = x - 7 and g(x) = x², which expression is equivalent to (gºf)(5? O (5-7)2
(5)²-7
O (5)? (5 – 7)
O (5-7) x²

(5^2)(5-7)

Step-by-step explanation:

So we know h(x)=x-7.

We also know g(x)=x^2

We need to plug in these values for (g*h)(5)

This would equal:

((x-7)*x^2)(5)

Since parthese can also be considered multipcation symbols, we can think of this as:

(x-7)(x^2)(5)

Lets distrubute the 5 to all the x's:

(5-7)(5^2)

Which is:

()(5-7)

This looks like answer C.

Hope this helps!

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

do you have a picture of the table