Given a box of 8 color crayons (Red, Blue, Green, Orange, Yellow, Brown, Black, Purple). If I remove a single crayon randomly, and without putting it back in the box, I remove a second crayon randomly, what is the probability that I will remove the Red and the Green crayon from the box

1/56

Step-by-step explanation:

Since the box has 8 different colors, the probability of picking any color of crayon will be 1/8.

This question relates to a probability without replacement, therefore, the probability of picking the red crayon first will be 1/8. After then, there'll be 7 crayons left and the probability of picking the green crayon next will be 1/7.

Therefore, the probability that I will remove the Red and the Green crayon from the box will be:

= 1/8 × 1/7

= 1/56

she was supposed to add the hours(38.5) and multiply the amount of money she earned(7.50) resulting in $288.75 .

correct me if i'm wrong and if it is i'm truly sorry.

5

step-by-step explanation: