I need the answer n 30 minutes, please! For which values of the parameter p equation
x ^ 2-px + 3 = 0
has a root in the range [0; 1], and another that does not belong to this range?

p = 4

Step-by-step explanation:

Given the expression x ^ 2-px + 3 = 0

If x = 0 is a solution

Substitute into the expression

0² - 0p + 3  = 0

-0p = -3

p = 3/0

p cannot be determined for this root

If x = 1

1² - 1p + 3 =0

1 - p + 3 = 0

-p+4 = 0

-p = -4

p = 4

Hence the va;ue of p is 4

1.4

2.3

step-by-step explanation:

the formula for the constant of variation is

y= kx

divide each side by x

y/x =kx/x

y/x =k

we know a and y

1.   y/x = k

4/1 =4

check the other values to make sure they are the same

8/2 = 4   12/3 =4   and 16/4 =4  

the constant of variation is 4

2.   y/x = k

3/1 =3

check the other values to make sure they are the same

6/2 = 3   9/3 =3   and 12/4 =3  

the constant of variation is 3

whats the question?

step-by-step explanation: