Which function has the greater x-intercept Function A X, 0,2,4,6 Y, 10,8,6,4 Function B y = -2x^2 + 1

function A

Step-by-step explanation:

First, we need to find the function of A. USing the coordinate points (0, 10) and (2,8)

Since y = mx+c

m = y2-y2/x2-x1

m = 8-10/2-0

m = -2/2

m = -1

From the coordinate (0, 10), the y-intercept is 10 i.e c = 10

The required equation is y = -x + 10

x intercept occurs at where y = 0

0 = -x+10

x =10

Hence the x-intercept of function A is 10

For Function B y = -2x^2 + 1

when y = 0

0 = -2x^2 + 1

2x^2 = 1

x^2 = 1/2

x = 1/√2

Hence the x intercept is 1/√2

Hence the function that has a greater y-intercept is function A

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic