Please help

Quadrilateral PQRS is shown. 4a + 1 (6x + 13) R 6b 11b - 10 Р (7x–5)°/ S 2a +9

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation:

what shape is