At a bus station, buses begin their routes at 6.Am. The schedule for two of the buses is based on time intervals listen below

They will both leave at 07:15am

Step-by-step explanation:

Given

Required

Next time both buses leave the station at the same time

To do this, we list out the multiples of 75 and 15.

We have:

After the first departure at 06:00 am (0 minutes) for both buses respectively, the next time they both leave is after 75 minutes (common multiple)

So, the time is:

2 5/8 is the final answer! : )

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.