if a box contains 7 red marbels, 6 white and 8 blue marbels and a marble is randomly selected from the box what is the probability that it is red expressed in fraction and in the simplest form​

1/3

Step-by-step explanation:

7 + 6 + 8 = 21 (There is a total of 21 marbles)

There are 7 red marbles, so the fraction should be 7/21 or 1/3

Have a great day :)

1/3

Step-by-step explanation:

How I got this answer is by adding 7+6+8 and I got 21. Then, I put the total of all of the marbles as the denominator which is 21. Next, I put 7 as the nominator so the fraction would be 7/21. Finally, I simplified 7/21 by 7 and I got 1/3.

where's the diagrams?