Tom has some marbles in two bags. In one bag he has 3 yellow, 2 green and 1 red marble. In the other bag he has 3 yellow, 3 green and 3 red marbles. If Tom takes one marble out of each bag, how probable is it that neither one is yellow? Include a chart of all the data you have.

1 / 3

Step-by-step explanation:

Bag 1 :

Yellow = 3

Green = 2

Red = 1

Total = 3 + 2 +1 = 6

Bag 2 :

Yellow = 3

Green = 3

Red = 3

Total = 3 + 3 + 3 = 9

P(not yellow from bag 1) = (green + red) / total = 3 /6 = 1/2

P(not yellow from bag 2) = (green + red) / total = 6/9 = 2 /3

P(neither is yellow) = 1/2 * 2/3 = 2 / 6 = 1/3

it should be a and d. lmk if i'm wrong xd