3x+5(2+x)=4x-7 help me out here?

x=

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3x+5(2+x)=4x−7

3x+(5)(2)+(5)(x)=4x+−7(Distribute)

3x+10+5x=4x+−7

(3x+5x)+(10)=4x−7(Combine Like Terms)

8x+10=4x−7

8x+10=4x−7

Step 2: Subtract 4x from both sides.

8x+10−4x=4x−7−4x

4x+10=−7

Step 3: Subtract 10 from both sides.

4x+10−10=−7−10

4x=−17

Step 4: Divide both sides by 4.

=

x=

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

can someone answer this question plz

step-by-step explanation: