1) If the perimeter of triangle STU is 125 cm, and segments TW, VW, and VT measure 21 cm, 30 cm, and 24 cm, respectively, what is the length of segment SU?​

GIVEN: The perimeter of triangle STU is  125.

The segments TW=21 cm

VW=30 cm

VT=24 cm

TO FIND: The length of the segment SU.

SOLUTION:

As corresponding sides must be same. so we have,

Then, TU=7k and TS=8k

As the perimeter of triangle STU is  125.

so,

8·k+7·k+10·k=125

⇒25.k=125

⇒k=5

Therefore, SU=10×5=50

assuming you mean addition: addition and subtraction are reverse operations.

step-by-step explanation:

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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