Find x if the average of 19, 12, 14, 18, and x is 12.

-3

Step-by-step explanation:

To do this, let's arrange it into an equation:

(19+12+14+18+x) / 5 = 12

Let's shift the 5 to the other side by multiplying 12 by 5, which is 60. Now the equation looks like this:

19+12+14+18 + x = 60

Now let's add 19, 12, 14 and 18 together, which is 63:

63 + x =60

Let's move the 63 over to the other side by subtracting it from 60, so 60-63 equals -3. Hence, the answer is -3. Hope this helps!

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)