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Mathematics, 31.05.2021 01:00 mathater15

The following system has one solution: x = 2, y = −2, and z = 3. 4x − 2y + 5z = 27 Equation 1
x + y = 0 Equation 2
−x − 3y + 2z = 10 Equation 3

1. Solve the system provided by Equations 1 and 3. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x, y, and z in terms of the parameter t.)
(x, y, z) =

2. Solve the system provided by Equations 2 and 3. (If there is no solution, enter NO SOLUTION. If the system has an infinite number of solutions, express x, y, and z in terms of the parameter t.)
(x, y, z) =

3. How many solutions does each of these systems have?
Equations 1 and 2:
(a)zero
(b) one
(c) infinitely many

Equations 1 and 3:
(a)zero
(b)one
(c)infinitely many

Equations 2 and 3:
(a)zero
(b)one
(c) infinitely many

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Answers: 2

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The following system has one solution: x = 2, y = −2, and z = 3. 4x − 2y + 5z = 27 Equation 1
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