Geometry please help.

CD = 16

Step-by-step explanation:

We can see that both AC and AB are radii. This means that they are equal, so AC = AB = 17. From segment addition postulate we can say AB = AE + BE

We are given BE, and we found the length of AB, so we can substitute and solve for AE:

AB = AE + BE

17 = AE + 2

AE = 15

Since we are given that AB is perpendicular to CD, ∠AEC would be a right angle, making ΔAEC a right triangle.

Now, we can use the pythagorean theorem to find the length of CE.

a^2 + b^2 = c^2

We are given the hypotenuse, c or AC in this case, and one leg, b, or AE in this case. We can plug in the values we are given:

CE^2 + AE^2 = AC^2

CE^2 + 15^2 = 17^2

CE^2 + 225 = 289

CE^2 = 64

CE = 8

Now, if a chord is perpendicular to a radius(AB in this case) we can say that it is split in half by the radius. This is basically saying that CE = DE = 8.

Again, using segment addition postulate, we can say:

CE + DE = CD

CD = 8 + 8

CD = 16

it would be a on edgenuit y

the diagram below is your final answer