Tenzing sold two watches at rs1200 andrs1350 respectively if he gained 20 percent on the first and 2percent on the whole what percent did he loss in second watch

9514 1404 393

  10% loss

Step-by-step explanation:

If Tenzing sold the first watch at 20% profit, his cost c can be found from ...

  1200 = 1.20c

  1000 = c

If Tenzing sold both watches together for 1200 +1350 = 2550, then his total cost can be found from ...

  2550 = 1.02t

  t = 2550/1.02 = 2500

Then his cost for the second watch was ...

  2500 -1000 = 1500

The sale price of 1350 for that watch represents a multiplier m on the watch cost of ...

  1500m = 1350

  m = 1350/1500 = 0.90 = 1 - 0.10

Tenzing lost 10% of its cost on the second watch.

the answer to this question is 3/19

step-by-step explanation: