what is the value of y in the following system of equations ? 2x + 3y = 6 2x + y = -2

y = 4

Step-by-step explanation:

2x + 3y = 6

2x + y = -2

Let's set the second equation equal to y. This means that y will be alone on one side of the equal sign.

2x + y = -2

Subtract 2x from both sides.

y = -2x - 2

Now that we have y as an expression, plug it into the first equation.

2x + 3y = 6

2x + 3(-2x - 2) = 6

Distribute the 3 across the parentheses by multiplying.

2x - 6x - 6 = 6

Combine like terms.

-4x = 12

Divide both sides by -4.

x = -3

Now we have solved x.

To solve for y, plug x back into one of the equations.

y = -2x - 2

y = -2(-3) - 2

Multiply.

y = 6 - 2

Subtract.

y = 4

Check your answer by plugging both values back into the original equations.

2x + 3y = 6

2(-3) + 3(4) = 6

Multiply.

-6 + 12 = 6

Add.

6 = 6

Your answer is correct.

Hope this helps!

y = 4

Step-by-step explanation:

2x + 3y = 6. #1

2x + y = -2. #2

Subtract Eq 2 from Eq 1,

3y - y = 6 - (-2)

2y = 8

or

y = 4

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step-by-step explanation:

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2