Pete can type 80 words in the same time that Ralph can type 50 words. If they type at those rates for an extended period of time, when Ralph has typed 4000 words, how many words has Pete
typed?

After the extended period of time, Pete would have typed 6400  words.

Step-by-step explanation:

Given the data in the question;

In the same time;

number typed word of Pete = 80

type word of Ralph = 50

After a period time;

number of typed word of Pete = ?

number of typed word of Ralph = 4000

so, let x represent the number of typed word by Pete after an extended period.

so

80 words = 50 words

x words =    4000 words

we cross multiply

x × 50 = 4000 × 80

x = ( 4000 × 80 ) / 50

x = 320000 / 80

x = 6400

Therefore, After the extended period of time, Pete would have typed 6400  words.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3