Triangle XYZ is reflected across the x-axis to produce triangle X'Y'Z'. Then triangle X'Y'Z' is rotated 90° counterclockwise about the origin to create triangle X"Y"Z". If triangle X"Y"Z" has vertices X"(4, 0), Y"(2, −1), Z"(2, 1) what are the coordinates of the vertices of triangle XYZ?

Step-by-step explanation:

produce triangle X'Y'Z'. Then triangle X'Y'Z' is rotated 90° counterclockwise about the origin to create triangle X"Y"Z". If triangle X"Y"Z" has vertices X"(4

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)