A clock is located on a wall, and the "12" on the face of the clock is 8 feet above the floor. A small mirror is placed on the floor so that it is between a student and the wall. The student's eyes are 5 feet above the floor, and the student is standing 4 feet from the mirror. The student sees the clock reflected in the mirror. How far from the base of the wall is the mirror located?

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intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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