What is the equivalent of (n+4)^3 ? A. n^3 +64
B. n^3 +6n² +24n+32
C. n^3+12n^2 + 48n + 64
D. n^3 +12n^2 +48n +32
E. n^3 +24n^2 +48n+64

C)

Step-by-step explanation:

(n+4)(n+4) = n² + 4n + 4n + 16

this can be simplified to get:

n² + 8n + 16

now multiply the above by (n+4)

(n²+8n+16)(n+4) by multiplying each of the three terms in the first set of parentheses by each of the two terms in the second set to get:

n³ + 4n² + 8n² + 32n + 16n + 64  [Now look to combine 'like terms']

n³ + 12n² + 48n + 64 [this is option C]

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

im pretty sure it would be 5 am, hope that , and give brainliest and guys if this is right then press the button and give 5 stars