Angle sec0= -13/12 and cot<0. what are the exact values of tan0 and sin0.

Solution given;

Sec θ=-

cotθ< 0,

It lies in second quadrant.

where sin and cosec is positive.

Now

cosθ=

=

b=12

h=13

By using Pythagoras law

p=

Now

exact values of tan θ==

since it lies in II quadrant

tan θ=-

and

sinθ==

since it lies in II quadrant

sin θ=

it's both, now can you answer my most recent question?

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)