Plot ΔABC on graph paper with points A(3,3), B(1,1), and C(6,1). Reflect ΔABC by multiplying the y-coordinates of the vertices by −1. Then use the function (x, y)→(x−6,y−3) to translate the resulting triangle. Name the coordinates of the vertices of the result. Question 3 options:

A'(-3,3), B'(-1,1), C'(-1,6)

A'(-6,-3), B'(-4,-5), C'(-4,0)

A'(3,-3), B'(1,-1), C'(6,-1)

A'(-3,-6), B'(-5,-4), C'(0,-4)

Plot ΔABC on graph paper with points A(10,4), B(-1,1), and C(4,2). Reflect ΔABC by multiplying the x-coordinates of the vertices by −1. Then use the function (x, y)→(x−5,y+4) to translate the resulting triangle. Name the coordinates of the vertices of the result.

Question 4 options:

A'(-4,-10), B'(-1,1), C'(-2,-4)

A'(-8,15), B'(-5,4), C'(-6,1)

A'(-10,4), B'(1,1), C'(-4,2)

A'(-15,8), B'(-4,5), C'(-9,6)

First one would be D (( A'(-3,-6), B'(-5,-4), C'(0,-4) ))

The second would be D (( A'(-15,8), B'(-4,5), C'(-9,6) )) as well

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step-by-step explanation:

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.