A square piece of paper has an area of x2 square units. A rectangular strip with a width of 2 units and a length of x units is cut off of the square piece of paper. The remaining piece of paper has an area of 120 square units. Which equation can be used to solve for x, the side length of the original square?

x2 − 2x − 120 = 0
x2 + 2x − 120 = 0
x2 − 2x + 120 = 0
x2 + 2x + 120 = 0

x² - 2x - 180 = 0

Step-by-step explanation:

A square piece of paper has an area of x² square units

w = x

l = x

A rectangular strip with a width of 2 units and a length of x units is cut off of the square piece of paper.

this leaves

l = x

w = x - 2

x(x - 2) = 180

x² - 2x = 180

x² - 2x - 180 = 0

A.) x² - 2x - 120 = 0

Step-by-step explanation:

Doing the exam on EDG right now (you might be doing a test or assignment- but ya) wish yall luck~ especially the ones doing the exam!

Have a good day! :3

step-by-step explanation:

i need to answer questions so i dont know but i think its the first one because it goes up but a consent rate

so, converting firstly the mixed fractions to improper fractions and then "adding".