Find h.
8 in.
h = [?] in.
6 in.
PLEASE HELP ME

h = in

Step-by-step explanation:

A right triangle is formed by h, slant height and radius

Here the legs are h and 6 ÷ 2 = 3, hypotenuse is 8

Using Pythagoras' identity in the right triangle

h² + 3² = 8²

h² + 9 = 64 ( subtract 9 from both sides )

h² = 55 ( take the square root of both sides )

h = in

sss (side, side, side)

sas (side, angle, side)

asa (angle, side, angle)

aas (angle, angle, side)

hl (hypotenuse, leg)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.