What is the measure of arc wx in the diagram below? 116"
Wo
45°
S
X
R
A. 116°
B. 45°
C. 710
D. 26°
someonee helpp plss

D

Step-by-step explanation:

The secant- secant angle WSX is half the difference of the intercepted arcs, that is

(116 - WX)° = 45° ( multiply both sides by 2 to clear the fraction )

116 - WX = 90° ( subtract 116° from both sides )

- WX = - 26° ( multiply both sides by - 1 )

WX = 26° → D

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

step-by-step explanation:

given expression is .

now we need to simplify the given expression .

we know that square root is equivalent to the power 1/2. so that means we can take half of the exponents to get the square root of given expression.

expanding that will give a very very large number so let's keep answer in exponent form.