QUESTION AND DIAGRAM IN PICTURE
CORRECT ANSWER = BRAINLIEST

The exact answer is 2*sqrt(5) but I figured it makes more sense to represent distance in terms of the approximate value. Round that however you need to. Your teacher may or may not want you to include the units, so be sure to ask.

Explanation:

This is similar to the previous question I answered earlier. Draw a vertical line straight down from point X until you reach line YZ. Mark point W on this vertical line, and that's also on line YZ.

Point W is the midpoint of YZ, which cuts it in half.

Let's focus on triangle WXY. It's horizontal leg is 8/2 = 4 km. Let a = 4.

For that same triangle, the vertical leg is unknown. We'll call it h. So b = h.

The hypotenuse of this right triangle is YX = 6 km. Let c = 6.

We have

Use the pythagorean theorem from here

a^2 + b^2 = c^2

4^2 + h^2 = 6^2

16 + h^2 = 36

h^2 = 36-16

h^2 = 20

h = sqrt(20)

h = sqrt(4*5)

h = sqrt(4)*sqrt(5)

h = 2*sqrt(5) exact

h = 4.47213595   approximate

h = 4.47 km

The distance is roughly 4.47 km

i hope this is what you were looking for.

see attached graph

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).