I NEED HELP PLEASE Triangle ABC is similar to triangle DEF. The length of AC¯¯¯¯¯ is 12 cm. The length of BC¯¯¯¯¯ is 18 cm. The length of DF¯¯¯¯¯ is 10 cm.

What is the length of EF¯¯¯¯¯?

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If the triangles are similar, the ratio of corresponding sides will be equal.

AC / DF = BC / EF

Substitute their values,

12 / 10 = 18 / EF

EF = 18/12 * 10

EF = 3/2 * 10

EF = 30/2

EF = 15 cm

In short, Your Answer would be 15 cm

Hope this helps!

y > 1/3x

y < = -x + 4

hope this : )

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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