Determine the decision criterion for rejecting the null hypothesis in the given hypothesis​ test; i. e., describe the values of the test statistic that would result in rejection of the null hypothesis. We wish to compare the means of two populations using paired observations. Suppose that d​3.125, ​2.911, and n​8, and that you wish to test the hypothesis below at the​ 10% level of significance. What decision rule would you​ use? ​: 0 against ​: 0

Decision Rule

The critical region for one tailed test with 7 d.f is t > 1.415 for

H0 : ud ≤ 0 against the claim Ha: ud > 0

Step-by-step explanation:

The data given is

Population mean = ud= 0

Sample difference mean = d`= 3.125

Sample difference standard deviation = sd= 2.911

Sample size= n= 8

Formulate the null and alternate hypotheses as

H0 : ud ≤ 0 against the claim Ha: ud>0

The significance level ∝= 0.1

The degrees of freedom = n-1 = 8-1 = 7

The critical region for one tailed test with 7 d.f is t > 1.415

The test statistic is

t= d`- ud/ sd/ √n

Putting the values

t= 3.125-0 / 2.911/√8

t= 3.125/1.0292

t= 3.036

since the calculated value of t falls in the critical region we reject the null hypothesis .

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>