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Sequence: 13, 20, 27

Rule: Tn = 7n + 6

Step-by-step explanation:

The 3 other numbers that can form an arithmetic progression is 13, 20, 27...

The nth term of an arithmetic progression is expressed as;

Tn = a + (n-1)d

a is the first term = 13

n is the number of terms

d is the common difference = 20 - 13 = 27 - 20

d = 7

Substitute

Tn = 13 + (n-1)(7)

Tn = 13 + 7n - 7

Tn = 7n+13-7

Tn = 7n + 6

This gives the required rule

5/12, or 5: 12

step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)