PLEASE HELP WITH A RIGHT ANSWER Arthur is a game show contestant and is offered a choice. He may accept $1500 cash or take a chance at playing a game where he could win $5000. The game consists of drawing two slips of paper from a hat, without replacement. The hat contains 10 slips of paper numbered with consecutive multiples of 4, beginning with 4 and ending with 40. If both slips of paper selected are less than 16, Arthur wins $5,000. If Arthur opts to play the game and loses, he does not receive any money at all. Which statement correctly explains the choice Arthur should make to win the most money? -arthur should accept the $1500 and not play the game. the mathematical expectation of the game is $450

$450

-Arthur should not accept the $1500 and play the game. The mathematical expectation of the game is $450

-Arthur should not accept the $1500 and play the game. The mathematical expectation of the game is $333.33

-Arthur should accept the $1500 and not play the game. The mathematical expectation of the game is $333.33​

a = 11 : 4

b = 38

c = 1 for every 6

c

c

c

c

c

c

c

cc

c

step-by-step explanation:

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages

6^2 or 36

step-by-step explanation:

6000n

6×1000n

6×10^3 n

so we need 6n need to be a perfect cube

so n has to be 6^2 so that 6n is 6^3

what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube