A thin wire inform of an equilateral triangle of side 11 cm find the area of a circle whose circumference is equal to the length of the wire

86.70 cm^2

Step-by-step explanation:

circumference = 11 x 3 = 33

circumference of a circle =  nD

33 = 3.14 X D

D = 10.51

r = 10.51 / 2 = 5.25

Area = nr^2

3.14 x 5.25^2 = 86.70 cm^2

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

h * s * a

h = history teacher

s = science teacher

a =   art teacher.

i see no data table, but just multiply the number of history teachers, science teachers, and art teachers.