In 1999, 2.2% of all cars in the United States were reported stolen. In a random sample of 400 Nissan Maxima cars 12 were reported stolen during 1999. If the percentage of thefts for Nissan Maxima cars is the same as the national percentage of 2.2%, what is the probability that the percentage of thefts ina random sample of 400 would be greater than or equal to 3%

The probability of  the percentage of thefts in a random sample of 400 would be greater than or equal to 3 is  given by  P (z> 1.09)   = 0.1379

Step-by-step explanation:

The statistic

z= p^- p / √pq/n

is used to measure the difference between the sample and population proportions.

Here p^= 12/400= 0.03

p= 0.022               q= 1-0.022=0.978

 and n=400

Putting the values

Z= 0.03-0.022/√0.022(1-0.022)/400

Z= 0.008/√0.022(0.978)/400

Z= 0.008/0.00733

z= 1.090

We have to find the probability of  the percentage of thefts in a random sample of 400 would be greater than or equal to 3

or

Mathematically

P (z> 1.09)= 1- P (z≤1.09)

                  = 1- 0.8621   ( from the z area table)

                   = 0.1379

x = 10.1

step-by-step explanation:

all of the angles of a tirangle add up to 180º

180 - 65 = 115 (since we already know the value of one angle)

(2x + 7) + (8x + 7) = 115

(combins like terms) 10x + 14 = 115

(isolate the variable subtract 14 from both sides): 10x = 101

(find the variable divide both sides by 10): x = 101/10

x = 10.1

she gotta workk that a 2

step-by-step explanation: