A chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture. The premium antifreeze solution contains 70% pure antifreeze. The company wants to obtain 140 gallons of a mixture that contains 20% pure antifreeze. How many gallons of water and how many gallons of the premium antifreeze solution must be mixed

40 gallons of premium antifreeze and 100 gallons of water should be used to obtain 140 gallons of a mixture that contains 20% pure antifreeze.

Step-by-step explanation:

Since a chemical company mixes pure water with their premium antifreeze solution to create an inexpensive antifreeze mixture, and the premium antifreeze solution contains 70% pure antifreeze, and the company wants to obtain 140 gallons of a mixture that contains 20% pure antifreeze, to To determine how many gallons of water and how many gallons of the premium antifreeze solution must be mixed, the following calculation must be performed:

50 x 0.7 + 50 x 0 = 35

40 x 0.7 + 60 x 0 = 28

30 x 0.7 + 70 x 0 = 21

29 x 0.7 + 71 x 0 = 20.3

28.57 x 0.7 + 71.43 x 0 = 20

140 x 0.2857 = 40

Therefore, 40 gallons of premium antifreeze and 100 gallons of water should be used to obtain 140 gallons of a mixture that contains 20% pure antifreeze.

2

step-by-step explanation:

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x