The difference between two numbers is 7. The sum of three times the larger number and twice the smaller number is 16. Drag and drop the correct options from the list menu to make each statement below true.

28 and 12 . (QUORA)

Step-by-step explanation:

Let’s write this down. We are looking for X and Y.

The difference between two numbers is 16: −=16

Three times the larger number is seven times the smaller:  ∗3=∗7

So, we need to solve X and Y from these two equations.

If we re-arrange X*3 = Y*7, we get Y = X*3/7.

So, −∗3/7=16 .  −∗3/7  is the same as  7∗/7−3∗/7 , or  4∗/7 . So  4∗/7=16−>4∗=7∗16−>=7∗4=28 .

Then we just go back to  −=16 , and  =28 , gives us  28−=16,  or  =28–16−>=12 .

So the numbers are 28 and 12.

answer: 12

step-by-step explanation:

3,6 and 7.

step-by-step explanation:

a) unit place of 37 is 7

so the unit place of cube of 37 will be

7³= 343=3

the answer is 3.

b) unit place of 56 is 6, so the unit place of cube of 56 will be

6³= 216=6

the answer is 6.

c) unit place of 133 is 3, so the unit place of cube of 133 will be

3³= 27= 7.

the answer is 7.