H(-4), h(0), h(4), h(8)
h(x)={-(x+1)^2 + 7, x<2
{-1/3x, x>4
h(-4)=
h(...
![subject](/tpl/images/cats/mat.png)
Mathematics, 25.05.2021 18:40 KrishnaBalaram1235
H(-4), h(0), h(4), h(8)
h(x)={-(x+1)^2 + 7, x<2
{-1/3x, x>4
h(-4)=
h(0)=
h(4)=
h(8)=
![ansver](/tpl/images/cats/User.png)
Answers: 1
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